A group of researchers developed a new method for ranking the total driving performance of golfers on a tour. The method requires knowing a golfer's average driving distance (yards) and driving accuracy (percent of drives that land in the fairway). They construct a straight-line model relating driving accuracy (y) to driving distance (x). A MINITAB printout with prediction and confidence intervals for a driving distance of x=300 is shown below.
MINITAB output
Predicted Values For New Observations
New Obs |
Fit |
SE Fit |
95% CI |
95% PI |
---|---|---|---|---|
1 |
61.303 |
0.359 |
(60.576, 62.030) |
(56.716, 65.890) |
Values of Predictors for New Observations
New Obs |
DISTANCE |
---|---|
1 |
300 |
a. Locate the 95% prediction interval for driving accuracy (y) on the printout, and give a practical interpretation of the result.
The 95% prediction interval is (56.716,65.890). (Round to three decimal places as needed.)
Give a practical interpretation of the result. Choose the correct answer below.
A.We are 95% confident that the actual driving accuracy for a golfer driving the ball 300 yards is between the limits of the prediction interval.Your answer is correct.
B.We are 95% confident that the mean driving accuracy for all golfers driving the ball 300 yards is between the limits of the prediction interval.
C.There is not enough information to answer this question.
b. Locate the 95% confidence interval for mean driving accuracy (y) on the printout, and give a practical interpretation of the result.
The 95% confidence interval is (60.576,62.030). (Round to three decimal places as needed.)
Give a practical interpretation of the result. Choose the correct answer below.
A.There is not enough information to answer this question.
B.We are 95% confident that the actual driving accuracy for a golfer driving the ball 300 yards is between the limits of the confidence interval.
C.We are 95% confident that the mean driving accuracy for all golfers driving the ball 300 yards is between the limits of the confidence interval.this answer is correct.
c. If you are interested in knowing the average driving accuracy of all golfers who have a driving distance of 300yards, which of the intervals is relevant? Explain. Choose the correct answer below.
A.There is not enough information to answer this question.
B.The confidence interval for the mean because it estimates the mean while the prediction interval for the actual value estimates a single value, not a mean.
C.The prediction interval for the single value because it estimates the single value while the confidence interval for the mean estimates the mean.
( a )
The 95% prediction interval is (56.716,65.890 )
interpretation :
Answer : Option ( A )
We are 95% confident that the actual driving accuracy for a golfer driving the ball 300 yards is between the limits of the prediction interval
( b )
The 95% confidence interval is (60.576,62.030 )
interpretation :
Answer : Option ( c )
.We are 95% confident that the mean driving accuracy for all golfers driving the ball 300 yards is between the limits of the confidence interval
( c )
Answer : Option ( B )
.We are 95% confident that the mean driving accuracy for all golfers driving the ball 300 yards is between the limits of the confidence interval
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