Question

A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 yellow. Three candies are pulled from the bag in succession, without replacement. What is the probability that the first two candies drawn are blue and the third is green?

Answer #1

A fun size bag of M&Ms has 4 blue, 3 orange, 3 red, 2
green, 2 yellow, and 1 brown M&Ms. What is the probability of
randomly selecting 5 M&Ms where 3 are blue and 2 are red?

M&Ms are multicolored candies in a bag with six colors:
Brown, Blue, Red, Yellow, Green and Orange. Mars now claims that
all six colors are equally likely. In an attempt to reject the
claim, an 8-oz bag of M&Ms was purchased and the colors
counted. The results of the count are below. Does this sample
contradict Mars’ claim when α = 0.10? Brown Blue Red Yellow Green
Orange 37 41 32 25 36 39 If the claim is true what...

According to M&Ms Web site, each package of the milk
chocolate candies typically contain 14% brown, 13% red, 14% yellow,
16% green, 24% blue, and 20% orange M&Ms. You go to the store
and buy a standard-sized package. When you open it, you find that
it contains 51 M&Ms, distributed as follows: Color Brown Red
Yellow Green Blue Orange Frequency 8 4 10 4 11 11 Over the long
run, what is the probability that the first M&M you select...

In a bag of M & M's, there are 80 M & Ms, with 11 red
ones, 12 orange ones, 20 blue ones, 10 green ones, 18 yellow ones,
and 9 brown ones. They are mixed up so that each candy piece is
equally likely to be selected if we pick one.
( ALL ANSWERS ROUNDED TO THREE DECIMAL PLACES)
a) If we select one at random, what is the probability that it is
yellow?
P(Yellow) ______________
b) If we...

A manufacturer of colored candies states that 13% of the
candies in a bag should be brown, 14% yellow, 13% red, 24%
blue, 20% orange, and 16% green. A student randomly selected a
bag of colored candies. He counted the number of candies of each
color and obtained the results shown in the table. Test whether the
bag of colored candies follows the distribution stated above at the
a=0.05 level of significance.
Color
Brown
Yellow
Red
Blue
Orange
Green
Frequency...

Grab your bag of M
& Ms and sort them out by color. Record the number of each
color in row A of the table below. Also record the total number of
M&Ms in your bag, n.
Calculate the expected
value of each color in a bag of size n. Record your results in Row
B.
Calculate the standard
deviation for each color in a bag of size n. Record your results in
Row C.
Using the
Range-Rule-Of-Thumb, calculate the...

1- A single serving of milk chocolate M&M candies is 50
pieces. In a standard bag of M&Ms there are six colors (brown,
yellow, green, red, orange, and blue) and assume equal
probabilities for the color of a randomly selected M&M.
a) What is the mean value for the number of red M&Ms in a
single serving of randomly selected M&Ms?
b)What is the variance of the number of red M&Ms in a single
serving?
c) What is the probability...

You have 150 M&Ms with 10% being green, 20% being blue, 30%
being orange and 40% being brown. Find the probability
of picking with replacement the following colors in succession Red,
Green, Brown. Round to 4 decimals.

M&M plain candies come in various colors. According to the
M&M/Mars Department of Consumer Affairs, the distribution of
colors for plain M&M candies is as follows.
Color
Purple
Yellow
Red
Orange
Green
Blue
Brown
Percentage
23%
17%
23%
7%
9%
8%
13%
Suppose you have a large bag of plain M&M candies and you
choose one candy at random.
(a) Find P(green candy or blue candy).
Are these outcomes mutually exclusive? Why?
No. Choosing a green and blue M&M is...

Your friend brings a large bag of candy to class. In the bag of
candy, there are 34 red candies, 47 blue candies, 23 orange
candies, 12 yellow candies, 38 green candies, and 87 purple
candies. Using this information answer the question below.
A) Before any candies have been taken out of the bag- what is
the probability of selecting each of the different types of
candies?
P(red candies)=
P(blue candies)=
P(orange candies)=
P( yellow candies)=
P( green candies)=
P(...

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