Question

se technology to find the P-value for the hypothesis test described below.

The claim is that for a smartphone carrier's data speeds at airports, the mean is

muμequals=12.00

Mbps. The sample size is

nequals=17

and the test statistic is

tequals=1.118

P-valueequals= 0.025

(Round to three decimal places as needed.)

Answer #1

**Solution:**

Given:

Claim: For a smartphone carrier's data speeds atairports, the mean is μ =12.00 Mbps.

Since claim is non-directional, this is two tailed test.

n = 17

thus df = degrees of freedom = n - 1 = 17 - 1 = 16

t = 1.118

We have to find P-value.

Use following steps in TI 84 plus calculator:

Press 2ND and VARS

Select tcdf(

Enter numbers

Click on Paste and press Enter two times.

Since this is two tailed test, thus multiply this answer by 2 , to get P-value for two tailed test.

P-value = 2 * 0.1400365456

P-value = 0.2800730911

**P-value = 0.280**

We can use Excel command:

=T.DIST.2T(x, df)

=T.DIST.2T(1.118,16)

=0.28007309

=0.280

**Thus P-value = 0.280**

se technology to find the P-value for the hypothesis test
described below.
The claim is that for a smartphone carrier's data speeds at
airports, the mean is
muμequals=16.00
Mbps. The sample size is
nequals=14
and the test statistic is
tequals=negative −2.404.
P-valueequals=nothing
(Round to three decimal places as needed.)
se technology to find the P-value for the hypothesis test
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The claim is that for a smartphone carrier's data speeds at
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described below. The claim is that for a smartphone carrier's data
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use technology to find the P- value for the hypothesis
test described below
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how is this entered into a TI 84

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The claim is that for a smartphone carrier’s data speeds at
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The display provided from technology available below results
from using data for a smartphone carrier's data speeds at airports
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The display provided from technology available below results
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LOADING...
Click the icon to view the display from technology.
Assuming all conditions...

Test the hypothesis using the P-value approach. Be sure to
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Upper H0:
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versus
Upper 1H :p
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xequals=205
alphaαequals=0.05
Is
np 0 left parenthesis 1 minus p 0 right
parenthesisnp01−p0greater than or equals≥10?
Use technology to find the P-value.
P-valueequals=nothing
(Round to three decimal places as needed.)

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