Question

se technology to find the​ P-value for the hypothesis test described below.

The claim is that for a smartphone​ carrier's data speeds at​ airports, the mean is

muμequals=12.00

Mbps. The sample size is

nequals=17

and the test statistic is

tequals=1.118

​P-valueequals= 0.025

​(Round to three decimal places as​ needed.)

Answer 1

Solution:

Given:

Claim: For a smartphone​ carrier's data speeds at​airports, the mean is μ =12.00 Mbps.

Since claim is non-directional, this is two tailed test.

n = 17

thus df = degrees of freedom = n - 1 = 17 - 1 = 16

t = 1.118

We have to find P-value.

Use following steps in TI 84 plus calculator:

Press 2ND and VARS

Select tcdf(

Enter numbers

Click on Paste and press Enter two times.

Since this is two tailed test, thus multiply this answer by 2 , to get P-value for two tailed test.

P-value = 2 * 0.1400365456

P-value = 0.2800730911

P-value = 0.280

We can use Excel command:

=T.DIST.2T(x, df)

=T.DIST.2T(1.118,16)

=0.28007309

=0.280

Thus P-value = 0.280