Nationwide, the amount charged by doctors for performing a particular minor surgical procedure averages $1525 and varies with a standard deviation of $375. We randomly select 50 bills from the population of all bills charged for this surgery. Let x represent the average amount charged for these 50 surgical procedures. Calculate the probability that the average amount charged for this procedure is more than $1200
Solution :
Given that,
mean = = $ 1525
standard deviation = = $ 375
n = 50
= = $ 1525
= / n = $ 375 / 50 = 53.03
P( > 1200) = 1 - P( < 1200)
= 1 - P[( - ) / < (1200 - 1525) / 53.03]
= 1 - P(z <-6.13)
Using z table,
= 1 - 0
= 1
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