Question

Use the pulse rates in beats per minute​ (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than 77 bpm. Use a 0.01significance level

Click the icon to view the pulse rate data.

59 38

95 92

105 90

81 94

77 78

101 69

47 45

78 90

80 104

75 87

63 61

66 48

35 54

49 39

90 35

97 92

71 83

105 38

102 58

86 98

89 43

40 57

102 100

84 70

69 41

test statistic?

p-value?

fail? why?

Answer 1

The null hypothesis being tested is Ho : mu < = 77

Ha : mu > 77

The test statistic is Z =n^1/2 *( x bar - mu) / s

Level of significance is 1% and right tailed.

Here n=50

X bar = 73

S square = sample variance (df =49) = 24488/49 =499.7

S = 22.35

putting this in the formula we get

Z= 7.07 * (73-77) /22.35

= 7.07 * (-4) /22.35=--28.28/22.35

=-1.26

The p value for this value of Z at 1% level of significance (one tailed) is 0.103835

As this is more than the level of significance of 1% we do not reject the null hypothesis.