A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 423 gram setting. It is believed that the machine is overfilling the bags. A 49 bag sample had a mean of 427 grams. Assume the population standard deviation is known to be 23. Is there sufficient evidence at the 0.05 level that the bags are overfilled?
Step 1 of 6: State the null and alternative hypotheses.
Step 2 of 6:Find the value of the test statistic. Round your answer to two decimal places.
Step 3 of 6: Specify if the test is one-tailed or two-tailed.
Step 4 of 6: Find the P-value of the test statistic. Round your answer to four decimal places.
Step 5 of 6: Identify the level of significance for the hypothesis test.
Step 6 of 6: Make the decision to reject or fail to reject the null hypothesis.
1)
H0: = 423
Ha: > 423
2)
Test statistics
z = - / / sqrt(n)
= 427 - 423 / 23 / sqrt(49)
= 1.22
3)
This is one tailed test.
4)
p-value = P( Z > z )
= P( Z > 1.22)
= 0.1112
5)
Level of significance = 0.05
6)
Since test statistics z > 0.05, we do not have sufficient evidence to reject H0.
We conclude that we fail to reject the null hypothesis.
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