Question Workspace Check My Work (2 remaining) The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 40 male consumers was $135.67, and the average expenditure in a sample survey of 30 female consumers was $68.64. Based on past surveys, the standard deviation for male consumers is assumed to be $38, and the standard deviation for female consumers is assumed to be $19.
A. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females (to 2 decimals)?
B. At 99% confidence, what is the margin of error (to 2 decimals)?
C. Develop a 99% confidence interval for the difference between the two population means (to 2 decimals). Use z-table. ( __,__ )
The statistical software output for this problem is:
Two sample Z summary confidence interval:
μ1 : Mean of population 1 (Std. dev. = 38)
μ2 : Mean of population 2 (Std. dev. = 19)
μ1 - μ2 : Difference between two means
99% confidence interval results:
Difference | n1 | n2 | Sample mean | Std. err. | L. limit | U. limit |
---|---|---|---|---|---|---|
μ1 - μ2 | 40 | 30 | 67.03 | 6.9378191 | 49.159362 | 84.900638 |
Hence,
a) Point estimate = 67.03
b) Margin of error = (84.90 - 49.16)/2 = 17.87
c) 99% confidence interval:
(49.16, 84.90)
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