Question

In a random sample of 47 dog owners enrolled in obedience training, it was determined that...

In a random sample of 47 dog owners enrolled in obedience training, it was determined that the mean amount of money spent per owner was $110.96 per class with a population standard deviation of $8.30. Construct and interpret a 95% confidence interval for the population mean amount spent per owner for an obedience class. A) ($108.52, $113.40); We are 95% confident that the population mean amount spent per dog owner for a single obedience class is between $108.52 and $113.40. B) ($108.52, $113.40); There is a 95% chance that a randomly selected dog owner will spend between $108.52 and $113.40 for a single obedience class. C) ($108.59, $113.33); There is a 95% chance that a randomly selected dog owner will spend between $108.59 and $113.33 for a single obedience class. D) ($108.59, $113.33); We are 95% confident that the population mean amount spent per dog owner for a single obedience class is between $109.59 and $113.33.

Homework Answers

Answer #1

The statistical software output for this problem is:

From above output, 95% confidence interval will be:

($108.59, $113.33); We are 95% confident that the population mean amount spent per dog owner for a single obedience class is between $109.59 and $113.33.

Option D is correct.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a random sample of 47 high-school students enrolled in SAT test training, it was determined...
In a random sample of 47 high-school students enrolled in SAT test training, it was determined that the mean amount of money spent per student was $110.96 per class with a sample standard deviation of $8.30. Construct and interpret a 95% confidence interval for the population mean amount spent per student for an SAT class. A) ($108.52, $113.40); We are 95% confident that the population mean amount spent per student for a single SAT class is between $108.52 and $113.40....
In a sample of 49 individuals, it is found that the average amount spent on groceries...
In a sample of 49 individuals, it is found that the average amount spent on groceries per month is $255. From previous studies, it is assumed that the population standard deviation is $46. Find a 95% confidence interval for the average amount of money spent on groceries per month, and interpret your result. Use ??=1.96 for 95% confidence, and round your answers to 2 decimal places. The confidence interval is: $ to $ This means: Select your answer from one...
In a sample of 40 individuals, it is found that the average amount spent on groceries...
In a sample of 40 individuals, it is found that the average amount spent on groceries per month is $255. From previous studies, it is assumed that the population standard deviation is $46. Find a 95% confidence interval for the average amount of money spent on groceries per month, and interpret your result. Use ??=1.96 for 95% confidence, and round your answers to 2 decimal places. The confidence interval is: $________ to $________ This means: Select your answer from one...
A survey of 90 randomly selected homeowners finds that they spend a mean of $66 per...
A survey of 90 randomly selected homeowners finds that they spend a mean of $66 per month on home maintenance. Assume that the population standard deviation is $13 per month. Construct and interpret a 95% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners.
A random sample of 58 randomly selected people were asked how much they spend on their...
A random sample of 58 randomly selected people were asked how much they spend on their grocery bill each week. The mean was $115.36 with a standard deviation of $16.6. Find a 95% confidence interval for the true population mean amount spent on groceries each week. Report the answer accurate to four decimal places.
A random sample of 14 ​men's resting pulse rates showed a mean of 71.5 beats per...
A random sample of 14 ​men's resting pulse rates showed a mean of 71.5 beats per minute and standard deviation of 19.9. Assume that pulse rates are Normally distributed. Use the table to complete parts​ (a) through​ (c) below. LOADING... Click the icon to view the​ t-table. a. Find a​ 95% confidence interval for the population mean pulse rate of​ men, and report it in a sentence. Choose the correct answer below​ and, if​ necessary, fill in the answer boxes...
Suppose that a random sample of 50 bottles of a particular brand of cough syrup is...
Suppose that a random sample of 50 bottles of a particular brand of cough syrup is selected and the alcohol content of each bottle is determined. Let μ denote the average alcohol content for the population of all bottles of the brand under study. Suppose that the resulting 95% confidence interval is (7.6, 9.2). (a) Would a 90% confidence interval calculated from this same sample have been narrower or wider than the given interval? Explain your reasoning. The 90% would...
A company tested 11 random brands of vanilla yogurt and found the number of calories per...
A company tested 11 random brands of vanilla yogurt and found the number of calories per serving given below.​ (Note that more than 110 different brands of vanilla yogurt​ exist.) 140   150    160    130    110    100    160    150    110    130    100     1) Find a​ 95% confidence interval for the average calorie content of vanilla yogurt per serving. 2) Interpret this interval for someone looking to buy yogurt A. A randomly selected serving of yogurt has a​ 90% chance of having...
Use this scenario for questions 1-5 Studies indicate that men are spending more money on personal...
Use this scenario for questions 1-5 Studies indicate that men are spending more money on personal care products. In a recent study, men are reported to spend on average $588 per year for personal care products. The population distribution of the amounts spent follows a normal distribution with a standard deviation of $45 per year. 1. What is the probability that a randomly selecting man spends $627.15 or more on personal care products?   Answer with three decimal places. 2.Which dollar...
Question 3 (1 point) You own a small storefront retail business and are interested in determining...
Question 3 (1 point) You own a small storefront retail business and are interested in determining the average amount of money a typical customer spends per visit to your store. You take a random sample over the course of a month for 42 customers and find that the average dollar amount spent per transaction per customer is $89.687 with a standard deviation of $10.9431. When creating a 99% confidence interval for the true average dollar amount spend per customer, what...