Assume that the heights of men are normally distributed with a mean of 69.3 inches and a standard deviation of 3.5 inches. If 100 men are randomly selected, find the probability that they have a mean height greater than 70.3 inches.
Solution :
Given that ,
mean = = 69.3
standard deviation = = 3.5
= / n = 3.5 / 100 = 0.35
P( > 70.3) = 1 - P( < 70.3)
= 1 - P[( - ) / < (70.3-69.3) /0.35 ]
= 1 - P(z < 2.86)
= 1 - 0.9979 = 0.0021,Probability = 0.0021
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