Consumers Energy states that the average electric bill across the state is $62.138. You want to test the claim that the average bill amount is actually greater than $62.138. The hypotheses for this situation are as follows: Null Hypothesis: μ ≤ 62.138, Alternative Hypothesis: μ > 62.138. A random sample of 28 customer's bills shows an average cost of $61.026 with a standard deviation of $7.3698. What is the test statistic and pvalue for this test?
Question 13 options:









PLEASE make sure your answer is correct, Thank You!
Solution :
This is the right tailed test .
The null and alternative hypothesis is ,
H_{0} : = 62.138
H_{a} : > 62.138
Test statistic = z
= (  ) / / n
= (61.026  62.138) / 7.3698 / 28
= 0.798
1  P(z < .798) = 1  0.2158 = 0.7842
Pvalue = 0.7842
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