Your friend has been collecting baseball cards. The company claims that you should have a 60% chance of finding a normal card, a 30% chance of finding an uncommon card, and a 10% chance of finding a rare card. Your friend has been opening packs of cards and collected 50 cards: 35 normal, 14 uncommon, and only 1 rare card.
Fill in the table below to find the Chi Square value of the baseball card sample.
applying chi square goodness of fit test: |
below is the chi square table:
relative | observed | Expected | residual | Chi square | |
category | frequency(p) | Oi | Ei=total*p | R2i=(Oi-Ei)/√Ei | R2i=(Oi-Ei)2/Ei |
normal | 0.60 | 35.0 | 30.00 | 0.91 | 0.833 |
uncommon | 0.30 | 14.0 | 15.00 | -0.26 | 0.067 |
rare | 0.10 | 1.0 | 5.00 | -1.79 | 3.200 |
total | 1.000 | 50 | 50 | 4.1000 | |
test statistic X2 = | 4.1000 | ||||
p value = | 0.1287 |
(please reply if further help is required on this)
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