Question

Suppose that are creatine kinase levels among healthy males are normally distributed with a standard deviation of 22 units/L research shows that exactly 5% of the healthy males have a creatine kinase level above 151 units / L what is the mean creatine level in healthy males? carry your intermediate computations to at least four decimal places. round your answer to one decimal place.

Answer #1

p(X > 151) = 0.05

Or, P((X - )/ > (151 - )/) = 0.05

Or, P(Z > (151 - )/22) = 0.05

Or, P(Z < (151 - )/22) = 0.95

Or, (151 - )/22 = 1.645

Or, = 151 - 22 * 1.645

Or, = 114.8

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