Question

An experiment involving disinfectants is repeated 15 times each for two different cleaning solutions. The first...

An experiment involving disinfectants is repeated 15 times each for two different cleaning solutions. The first solution had a sample mean of 3.73 and sample standard deviation of 2.781 and the second solution had a sample mean of 4.8 and a sample standard deviation of 0.1715. Assuming both populations are normal, find the observed level of statistical significance that the population variances are different.

Homework Answers

Answer #1

Since you have not mentioned the level of significance so I will assume it 0.05

NULL HYPOTHESIS H0:

ALTERNATIVE HYPOTHESIS Ha:

alpha=0.05

F= (s1)^2/(s2)^2

F= (2.781)^2/(0.1715)^2

F= 262.9503

df1= n1-1= 15-1=14

df2= n2-1= 15-1=14

F critical= 2.48

Since F critical is SMALLER than Fcal we therefore REJECT null hypothesis H0 and

Conclusion: We have sufficient evidence to conclude that the population variances are different.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An experiment was conducted to compare the alcohol content of soy sauce on two different production...
An experiment was conducted to compare the alcohol content of soy sauce on two different production lines. Production was monitored eight times a day in both production lines. Production line 1 has a sample standard deviation of 0.16 and Production line 2 has a sample standard deviation of 0.11. Assume both populations are normal. State and conclude your hypothesis at the 0.05 level of significance if the both of production lines have the same variability?
An experiment was performed to compare the degradation of two different tools. Twelve samples of tool...
An experiment was performed to compare the degradation of two different tools. Twelve samples of tool 1 were tested and ten samples of tool 2 were tested. In each case, the degradation was observed. The samples for tool 1 gave an average degradation of 15 units with a sample standard of 4, while the sample for tool 2 gave an average of 11 with a sample standard deviation of 5. Assume the population to be approximately normal. (a) Use a...
An administrator claims that the average test scores between two instructors at a school are different....
An administrator claims that the average test scores between two instructors at a school are different. In a sample of 28 students from the first instructor’s class, the average test score was 32 out of 50 points with a standard deviation of 5 points. In a sample of 33 students from the second instructor’s class, the average was 29 out of 50 with a standard deviation of 6 points. Assuming both populations are normally distributed and the population variances are...
Two friends, Karen and Jodi, work different shifts for the same ambulance service. They wonder if...
Two friends, Karen and Jodi, work different shifts for the same ambulance service. They wonder if the different shifts average different numbers of calls. Looking at past records, Karen determines from a random sample of 35 shifts that she had a mean of 5.2 calls per shift. She knows that the population standard deviation for her shift is 1.3 calls. Jodi calculates from a random sample of 34 shifts that her mean was 4.8 calls per shift. She knows that...
Fairfield Homes is developing two parcels near Pigeon Forge, Tennessee. In order to test different advertising...
Fairfield Homes is developing two parcels near Pigeon Forge, Tennessee. In order to test different advertising approaches, it uses different media to reach potential buyers. The mean annual family income for 18 people making inquiries at the first development is $162,000, with a standard deviation of $40,000. A corresponding sample of 29 people at the second development had a mean of $181,000, with a standard deviation of $29,000. Assume the population standard deviations are the same. At the 0.01 significance...
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising...
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising approaches, it uses different media to reach potential buyers. The mean annual family income for 15 people making inquiries at the first development is $156,000, with a standard deviation of $44,000. A corresponding sample of 27 people at the second development had a mean of $182,000, with a standard deviation of $32,000. Assume the population standard deviations are the same. At the 0.05 significance...
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising...
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising approaches, it uses different media to reach potential buyers. The mean annual family income for 17 people making inquiries at the first development is $160,000, with a standard deviation of $39,000. A corresponding sample of 29 people at the second development had a mean of $174,000, with a standard deviation of $32,000. Assume the population standard deviations are the same. At the 0.10 significance...
A study was designed to compare the attitudes of two groups of nursing students towards computers....
A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 15 nursing students from Group 1 resulted in a mean score of 59.6 with a standard deviation of 8.1. A...
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising...
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising approaches, it uses different media to reach potential buyers. The mean annual family income for 18 people making inquiries at the first development is $165,000, with a standard deviation of $36,000. A corresponding sample of 28 people at the second development had a mean of $179,000, with a standard deviation of $25,000. Assume the population standard deviations are the same. At the 0.02 significance...
A study was designed to compare the attitudes of two groups of nursing students towards computers....
A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 1010 nursing students from Group 1 resulted in a mean score of 45.345.3 with a standard deviation of 4.54.5. A...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT