Question

The numbers of successes and the sample sizes for independent simple random samples from two populations are x1=15, n1=30, x2=59, n2=70. Use the two-proportions plus-four z-interval procedure to find an 80% confidence interval for the difference between the two populations proportions. What is the 80% plus-four confidence interval?

Answer #1

The numbers of successes and the sample sizes for independent
simple random samples from two populations are x 1equals32, n
1equals40, x 2equals10, n 2equals20. a. Use the two-proportions
plus-four z-interval procedure to find an 95% confidence interval
for the difference between the two populations proportions. b.
Compare your result with the result of a two-proportion
z-interval procedure, if finding such a confidence interval is
appropriate.

Independent random samples were selected from two quantitative
populations, with sample sizes, means, and standard deviations
given below. n1 = n2 = 80, x1 = 125.3, x2 = 123.6, s1 = 5.7, s2 =
6.7
Construct a 95% confidence interval for the difference in the
population means (μ1 − μ2). (Round your answers to two decimal
places.)
Find a point estimate for the difference in the population
means.
Calculate the margin of error. (Round your answer to two decimal
places.)

rovided below are summary statistics for independent simple
random samples from two populations. Use the pooled t-test and the
pooled t-interval procedure to conduct the required hypothesis
test and obtain the specified confidence interval. X1=20, S1=6,
N1=21, X2=22, S2=7, N2= 15 Left tailed test, a=.05 90% confidence
interval The 90% confidence interval is from ____ to ____

Two random samples are selected from two independent
populations. A summary of the samples sizes, sample means, and
sample standard deviations is given below:
n1=41, n2=44, x¯1=52.3, x¯2=77.3, s1=6 s2=10.8
Find a 96.5% confidence interval for the difference μ1−μ2 of the
means, assuming equal population variances.
Confidence Interval =

Two random samples are selected from two independent
populations. A summary of the samples sizes, sample means, and
sample standard deviations is given below:
n1=39,n2=40,x¯1=50.3,x¯2=73.8,s1=6s2=6.1
Find a 98% confidence interval for the difference μ1−μ2 of the
population means, assuming equal population variances.

Two random samples are selected from two independent
populations. A summary of the samples sizes, sample means, and
sample standard deviations is given below:
n1=51,n2=36,x¯1=56.5,x¯2=75.3,s1=5.3s2=10.7n1=51,x¯1=56.5,s1=5.3n2=36,x¯2=75.3,s2=10.7
Find a 97.5% confidence interval for the difference μ1−μ2μ1−μ2
of the means, assuming equal population variances.
Confidence Interval =

Independent random samples of
n1 = 600
and
n2 = 440
observations were selected from binomial populations 1 and 2,
and
x1 = 334
and
x2 = 378
successes were observed.
(a) Find a 90% confidence interval for the difference
(p1 − p2) in the two
population proportions. (Round your answers to three decimal
places.)
to
(b) What assumptions must you make for the confidence interval to
be valid? (Select all that apply.)
independent samples
random samples
nq̂ > 5...

Independent random samples of
n1 = 700
and
n2 = 590
observations were selected from binomial populations 1 and 2,
and
x1 = 337
and
x2 = 375
successes were observed.
(a) Find a 90% confidence interval for the difference
(p1 − p2) in the two
population proportions. (Round your answers to three decimal
places.)

Two random samples are selected from two independent
populations. A summary of the samples sizes, sample means, and
sample standard deviations is given below:
n1=45,n2=40,x¯1=50.7,x¯2=71.9,s1=5.4s2=10.6 n 1 =45, x ¯ 1 =50.7, s
1 =5.4 n 2 =40, x ¯ 2 =71.9, s 2 =10.6
Find a 92.5% confidence interval for the difference μ1−μ2 μ 1 −
μ 2 of the means, assuming equal population variances.

Two samples are taken with the following numbers of successes
and sample sizes
r1 = 27 r2 = 37
n1 = 84 n2 = 54
Find a 96% confidence interval, round answers to the nearest
thousandth.
< p1−p2 <

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