Range Minimum: | 13.1 | |||
Range Maximum: | 85.5 | |||
Median: | 27.3 | |||
Mode: | #N/A | |||
x̅ | 38.1 | |||
n | 21 | |||
s2 | 499.5783 | |||
s | 22.35125 | |||
Calculate the standard error of the mean. | ||||
sx̅ | ||||
If we assume our data is a random sample, we are 95% confident that the population mean falls between ___ and ____. Fill in the blanks. | ||||
If we assume our data is a random sample, we are 99% confident that the population mean falls between ___ and ____. Fill in the blanks. |
std.error of the mean = 22.35125/sqrt(21))
= 4.8774
t value at 95% = 2.086
CI = xbar +/- t *SE
= 38.1 +/- 2.086 * 4.8774
= (27.9257 , 48.2743)
If we assume our data is a random sample, we are 95% confident that the population mean falls between 27.9257 and 48.2743
t value at 99% = 2.845
CI = xbar +/- t *SE
= 38.1 +/- 2.845 * 4.8774
= (24.2238 , 51.9762)
If we assume our data is a random sample, we are 99% confident that the population mean falls between 24.2238 and 51.9762
Get Answers For Free
Most questions answered within 1 hours.