Mean Wait Time: Not In Program | Mean Wait Time: In Program | |
315 | 193 | |
328 | 230 | |
278 | 246 | |
312 | 146 | |
270 | 196 | |
189 | 251 | |
261 | 190 | |
224 | 232 | |
275 | 194 | |
325 | 195 | |
291 | 195 | |
243 | 238 | |
257 | 275 | |
319 | 249 | |
261 | 262 | |
291 | 231 | |
251 | 281 | |
234 | 193 | |
257 | 322 | |
341 | 190 | |
313 | 234 | |
271 | 268 | |
246 | 260 | |
340 | 223 | |
318 | 265 | |
234 | 228 | |
214 | 194 | |
250 | 295 | |
241 | 241 | |
291 | 276 |
The owners of an ice cream shop franchise, looking to reduce wait times for customers, launched a pilot program where customers could use a smartphone app to place orders. The accompanying data set shows the mean wait times (in seconds) for in-store and drive-through customers at 30 shops participating in the pilot program and at 30 shops not in the program. Assume that the population variance of mean wait times is equal for both groups and that the mean wait times are normally distributed for both groups. Let the mean wait times of the shops not in the program be the first sample, and let the mean wait times of the shops in the program be the second sample. At the 0.10 level of significance, is there evidence that the smartphone app reduces wait times? Perform the test using Excel. Find the test statistic, rounded to two decimal places, and the p-value, rounded to three decimal places. |
Following is the output of t test generated by excel:
The test statistics is
t = 4.10
The p-value is: 0.000
Since p-value is less than 0.10 so we reject the null hypothesis. That is we can conclude that the smartphone app reduces wait times.
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