Bob is planning to pack 6 shirts and 4 pairs of pants for a trip. If he has 8 shirts and 7 pairs of pants to choose from, in how many different ways can this be done?
As the order of selection of shirts does not matter, number of different ways Bob can select 6 shirts from 8 shirts is
8C6 = 8! / ((8-6)! 6!) = 8! / (2! 6!)
= (8 * 7) / (2 * 1)
= 28
As the order of selection of pairs of pants does not matter, number of different ways Bob can select 4 pairs of pants from 7 is
7C4 = 7! / ((7-4)! 4!) = 7! / (3! 4!)
= (7 * 6 * 5) / (3 * 2 * 1)
= 35
Number of different ways to pack 6 shirts and 4 pairs of pants for a trip is,
28 * 35 = 980
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