Question

The time required to assemble an electronic component is normally distributed with a mean and a...

The time required to assemble an electronic component is normally distributed with a mean and a standard deviation of 17 minutes and 9 minutes, respectively. [You may find it useful to reference the z table.] a. Find the probability that a randomly picked assembly takes between 15 and 22 minutes. (Round "z" value to 2 decimal places and final answer to 4 decimal places.) b. It is unusual for the assembly time to be above 29 minutes or below 7 minutes. What proportion of assembly times fall in these unusual categories? (Round "z" value to 2 decimal places and final answer to 4 decimal places.)

Homework Answers

Answer #1

Solution :

Given that ,

mean = = 17

standard deviation = = 9

a)

P(15 < x < 22) = P((15-17)/ 9) < (x - ) /  < (22-17) / 9) )

= P(-0.22 < z < 0.56)

= P(z < 0.56) - P(z < -0.22)

= 0.7123 - 0.4129

= 0.2994

Probability = 0.2994

b)

P(x > 29) + P(x < 7) = (1 - P(x < 29) )+ P(x < 7)

= (1 - P((x - ) / < (29-17) / 9) )+ P((x - ) / < (7-17) / 9)

= (1 - P(z < 1.33)) + P(z < -1.11)

= (1 - 0.9082) + 0.1335   

= 0.0918 + 0.1335

= 0.2253

Proportion = 0.2253

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The time required to assemble an electronic component is normally distributed with a mean and a...
The time required to assemble an electronic component is normally distributed with a mean and a standard deviation of 24 minutes and 16 minutes, respectively. [You may find it useful to reference the z table.] a. Find the probability that a randomly picked assembly takes between 19 and 29 minutes. (Round "z" value to 2 decimal places and final answer to 4 decimal places.) b. It is unusual for the assembly time to be above 45 minutes or below 7...
The time required to assemble an electronic component is normally distributed with a mean and a...
The time required to assemble an electronic component is normally distributed with a mean and a standard deviation of 24 minutes and 13 minutes, respectively. [You may find it useful to reference the z table.] a. Find the probability that a randomly picked assembly takes between 19 and 27 minutes. (Round "z" value to 2 decimal places and final answer to 4 decimal places.) b. It is unusual for the assembly time to be above 43 minutes or below 9...
The time required to assemble an electronic component is normally distributed with mean 12.6 minutes and...
The time required to assemble an electronic component is normally distributed with mean 12.6 minutes and a standard deviation of 4.2 minutes. Find the probability that a particular assembly takes the following length of time. 3.1) Between 12.6 and 17.7 minutes. (3) 3.2) Less than 5.5 minutes (3) 3.3) More than 6.1 minutes (3)
Question (2): [10 marks]: The time required to assemble an electronic component is normally distributed with...
Question (2): [10 marks]: The time required to assemble an electronic component is normally distributed with a mean of 12 minutes and a standard deviation of 1.5 minutes a) [2 points] Find the probability that a particular assembly takes more than 14.25 minutes. b) [2 points] Find (x) the 75th percentile of time required to assemble an electronic component. c) [3 points] The company wants to increase productivity. One strategy they are discussing is to ensure that 75% of their...
The amount of time required to assemble a component on a factory assembly line is normally...
The amount of time required to assemble a component on a factory assembly line is normally distributed with a mean of 3.1 minutes and a standard deviation of 0.6 minute. Find the probability that a randomly selected employee will take the given amount of time to assemble the component. (Round your answers to four decimal places.) (a) more than 3.8 minutes (b) between 1.8 and 2.5 minutes
The amount of time required to assemble a component on a factory assembly line is normally...
The amount of time required to assemble a component on a factory assembly line is normally distributed with a mean of 3.1 minutes and a standard deviation of 0.7 minute. Find the probability that a randomly selected employee will take the given amount of time to assemble the component. (Round your answers to four decimal places.) (a) more than 3.7 minutes (b) between 1.8 and 2.6 minutes
The superior of a product line belives that the average time to assemble an electronic component...
The superior of a product line belives that the average time to assemble an electronic component is 14 min. Assume that assembly time is normaly distributed with a standard deviation of 3.4 minutes. The supervisor times the assembly of 14 components and finds that the average time for competition is 11.6. What are approciate null and alternativ hypotheses? Which is most accurate 1.Reject the null hypothesis at a<0.10 2. Fail to reject the null hypothesis at a< 0.10 or a=0.10...
Let X be normally distributed with mean μ = 126 and standard deviation σ = 22....
Let X be normally distributed with mean μ = 126 and standard deviation σ = 22. [You may find it useful to reference the z table.] a. Find P(X ≤ 100). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) b. Find P(95 ≤ X ≤ 110). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) c. Find x such that P(X ≤ x) = 0.410. (Round "z" value and...
Let X be normally distributed with mean μ = 10 and standard deviation σ = 6....
Let X be normally distributed with mean μ = 10 and standard deviation σ = 6. [You may find it useful to reference the z table.] a. Find P(X ≤ 0). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) b. Find P(X > 2). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) c. Find P(4 ≤ X ≤ 10). (Round "z" value to 2 decimal places and final...
Let X be normally distributed with mean μ = 12 and standard deviation σ = 6....
Let X be normally distributed with mean μ = 12 and standard deviation σ = 6. [You may find it useful to reference the z table.] a. Find P(X ≤ 0). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) b. Find P(X > 3). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) c. Find P(6 ≤ X ≤ 12). (Round "z" value to 2 decimal places and final...