Question

Perform a Spearman Rank Correlation Coefficient Test at a significance of 0.05. Use the following data points

Height (in.) | Foot Length (in.) |

63 | 10 |

66 | 12 |

62.5 | 9.4 |

74 | 10.5 |

70 | 11.3 |

72 | 11.3 |

71 | 12.5 |

64 | 9.1 |

72 | 10.9 |

71 | 10 |

74 | 12.1 |

67 | 10 |

69 | 11.1 |

65 | 9.6 |

62.8 | 9 |

72 | 11.3 |

68.8 | 10.5 |

69 | 10 |

65.3 | 9 |

53 | 7 |

71 | 10.3 |

74 | 11.7 |

70 | 10 |

72 | 10.6 |

72.5 | 12.8 |

67 | 9.5 |

69 | 10.9 |

74 | 11.6 |

68 | 9 |

70.1 | 10.1 |

62 | 8 |

77 | 11.4 |

63 | 9.5 |

64.5 | 9.4 |

71 | 9.8 |

Answer #1

**Solution:**

Using the data below, compute the following predicted
values.
70 62.5
69 64.6
64 69.1
71 73.9
68 67.1
66 64.4
74 71.1
73 71.0
62 67.4
69 69.3
67 64.9
68 68.1
72 66.5
66 67.5
72 66.5
68 70.3
71 67.5
67 68.5
71 71.9
75 67.8
64 58.6
65 64.7
67 65.3
72 61.0
72 65.4
72 67.4
67 60.9
71 63.1
66 60.0
75 71.1
69 62.2
70 67.2
69 63.4
62 68.4
66 62.2
76...

3. (a) Use the sample to make a point estimate of the mean
height of the entire female/male SCC student body.
(b) Construct a 93% confidence interval for the mean height of
the entire female/male SCC student body.
(c) What is the width of this interval?
(d) Write a sentence interpreting your confidence interval.
male Student # Gender Height Shoe Age Hand
1 M 67 10 19 R
2 M 74 12 17 R
3 M 72 11.5 19 R...

BODYFAT
HEIGHT
12.9
67.75
6
72.25
25.5
66.25
10.6
72.25
28.1
71.25
20
74.75
19.2
69.75
11.9
72.5
4.3
74
12.9
73.5
7.6
74.5
8.3
76
20.4
69.5
19.8
71.25
22.2
69.5
20.9
66
28
71
23
71
15.6
67.75
16.9
73.5
18.5
68
15.5
69.75
14.7
68.25
18
70
13.6
67.75
4.3
71.5
8
67.5
22.4
67.5
4.4
64.75
8.9
69
13.2
73.75
6.3
71.25
12.6
71.25
21
71
31.9
73.5
39.1
65
23.2
70
26.6
68.25
34.3
72.25...

MALE :Student # Gender Height Shoe Age Hand
1 M 67 10 19 R
2 M 74 12 17 R
3 M 72 11.5 19 R
4 M 69 10 35 R
5 M 66 9 18 R
6 M 71 10.5 17 R
7 M 72 10.5 17 R
8 M 66 10 20 R
9 M 67 10 18 R
10 M 71 10.5 24 R
11 M 66 10 21 R
12 M 71 10.5 18 R...

Student Grades
Student
Test
Grade
1
76
62
2
84
90
3
79
68
4
88
84
5
76
58
6
66
79
7
75
73
8
94
93
9
66
65
10
92
86
11
80
53
12
87
83
13
86
49
14
63
72
15
92
87
16
75
89
17
69
81
18
92
94
19
79
78
20
60
71
21
68
84
22
71
74
23
61
74
24
68
54
25
76
97...

You wish to test the following claim (Ha) at a significance
level of α=0.02.
Ho: μ1 = μ2
Ha: μ1 ≠ μ2
You obtain the following two samples of data.
Sample #1
Sample #2
85.1
56.6
74.4
72
72.8
77.6
76.4
70.2
54.5
76.9
65.6
54.5
67.2
86.9
84.4
68.4
73.2
74.8
80.7
70.4
76
74.2
86.9
83.8
54.5
67.4
60.4
63
72.4
85.9
78.9
85.9
69
68.4
64.1
73.6
67
68.8
59.7
85.9
58.6
71.4
57.6
72.6
73.9
83.1...

Table 1. Use the information to calculate the following
TC, AFC, AVC, ATC, AND MC (I through 50)
TP
TFC
TVC
TC
AFC
AVC
ATC
MC
150
0
(1)
(11)
(21)
(31)
(41)
2
150
70
(2)
(12)
(22)
(32)
(42)
3
150
130
(3)
(13)
(23)
(33)
(43)
4
150
240
(4)
(14)
(24)
(34)
(44)
5
150
300
(5)
(15)
(25)
(35)
(45)
6
150
360
(6)
(16)
(26)
(36)
(46)
7
150
390
(7)
(17)
(27)
(37)...

Consider the following SAS code and data:
DATA SCHOOL;
LENGTH GENDER $ 1 TEACHER $ 5;
INPUT SUBJECT
GENDER $
TEACHER $
T_AGE
PRETEST
POSTTEST;
GAIN = POSTTEST - PRETEST;
DATALINES;
1 M JONES 35 67 81
2 F JONES 35 98 86
3 M JONES 35 52 92
4 M BLACK 42 41 74
5 F BLACK 42 46 76
6 M SMITH 68 38 80
7 M SMITH 68 49 71
8 F SMITH 68 38 63
9...

3. (Lesson 11) Use Minitab Express to conduct a
chi-square test to determine if there is a relationship between
gender and whether the student said that they would prefer to win
an Academy Award, Nobel Prize, or Olympic Medal. Use the
five-step hypothesis testing procedure. [25 points]
Step 1: State hypotheses and check
assumptions
Step 2:Compute the test
statistic
Step 3: Determine the
p-value
Step 4: Make a decision (reject or fail
to reject the null)
Step 5: State a real...

Data was collected for 364 randomly selected 10 minute
intervals. For each ten-minute interval, the number of people
entering the atrium of a large mall were recorded. The data is
summarized in the table below.
Number
of Guests
Frequency
220 – 239
83
240 – 259
95
260 – 279
47
280 – 299
43
300 – 319
96
What is the class width for this GFDT?
Class width =
The number of students in the tutoring center was recorded...

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