One year, there were about 3,000 institutions of higher learning in the U.S. including community colleges and junior college. As part of a continuing study of higher education, the Carnegie Commission took a simple random sample of 400 of those institutions. The average enrollment in the 400 sample schools was 3,700, and the standard deviation was 6,500. Find a 68% confidence interval for the average enrollment of all 3.000 institutions. (You may assume that the box is NOT lopsided)
Formula for Confidence Interval for Population mean when population Standard deviation is not known
Given | |
Sample Mean : : Sample average enrollment | 3700 |
Sample Standard Deviation : s | 6500 |
Sample Size : n : Number of institutions in the random sample | 400 |
Degrees of freedom : n-1 | 399 |
Confidence Level : | 68 |
= (100-68)1/00 | 0.32 |
/2 | 0.16 |
0.9957 |
68% confidence interval for the average enrollment of all 3.000 institutions
68% confidence interval for the average enrollment of all 3.000 institutions = (3376.3975,4023.6025)
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