Previously, 5% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 5% today. She randomly selects 145 pregnant mothers and finds that 4 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the α=0.05 level of significance.
What are the null and alternative hypotheses?
H0:p =0.05 versus H1: p <0.05
(Type integers or decimals. Do not round.)
Because np0(1 - p0)=____ < 10, the normal model (may/may not) be used to approximate the P-value.
(Round to one decimal place as needed.)
Find the P-value.
P-value=____
(Round to three decimal places as needed.)
Is there sufficient evidence to support the obstetrician's statement?
A. No, do not reject the null hypothesis because the P-value is greater than α. There is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5%.
B. Yes, reject the null hypothesis because the P-value is less than α. There is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5%.
C. Yes, do not reject the null hypothesis because the P-value is greater than α. There is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5%.
D. No, reject the null hypothesis because the P-value is less than α. There is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5%.
The statistical software output for this problem is:
Hence,
Because np0(1 - p0)= 6.9 < 10, the normal model may not be used to approximate the P-value.
P-value = 0.108
No, do not reject the null hypothesis because the P-value is greater than α. There is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5%.
Option A is correct.
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