Question

1- Assume the time to complete a task has a normal distribution with mean 20 min....

1-

Assume the time to complete a task has a normal distribution with mean 20 min. and standard deviation 4 min.

Find the proportion of times that are BETWEEN 15 and 25 minutes?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 7 is entered as 7.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

2-

Assume the time to complete a task has a normal distribution with mean 20 min. and standard deviation 4 min.

Find the proportion of times that are ABOVE 22 minutes?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 7 is entered as 7.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

3-

Assume the time to complete a task has a normal distribution with mean 20 min. and standard deviation 4 min.

Find the proportion of times that are BELOW 15 minutes?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 7 is entered as 7.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

4-

Assume the time to complete a task has a normal distribution with mean 20 min. and standard deviation 4 min.

Find the cutoff for the 67th percentile of task times

Note: Enter X.X AT LEAST ONE DIGIT BEFORE THE DECIMAL, ONE AFTER and round up. Thus, 7 is entered as 7.0, 19.248 is entered as 19.2, 25.551 is entered as 25.6

5-

Assume the time to complete a task has a normal distribution with mean 20 min. and standard deviation 4 min.

What is the cutoff for the UPPER 10% of task times?

Note: Enter X.X AT LEAST ONE DIGIT BEFORE THE DECIMAL, ONE AFTER and round up. Thus, 7 is entered as 7.0, 19.248 is entered as 19.2, 25.551 is entered as 25.6

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