3) There were 47 people that took the last statistics exam. The standard deviation was 9.8 points.
Create a 98% confidence interval for the standard deviation.
Does is seem possible that the overall standard deviation is 15?
Chi square critical values at 0.02 level with 46 df = 26.657 , 71.201
98% confidence interval for is
Sqrt [ (n-1) S2 / /2 ] < < Sqrt [ (n-1) S2 / 1-/2 ]
Sqrt [ 46 * 9.82 / 71.201 ] < < Sqrt [ 46 * 9.82 / 26.657 ]
7.877 < < 12.873
98% CI for is ( 7.877 , 12.873 )
Since 15 is not lies in confidence interval, we do not have sufficient evidence to support the claim.
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