The data below are yields for two different types of corn seed that were used on adjacent plots of land. Assume that the data are simple random samples and that the differences have a distribution that is approximately normal. Construct a 95% confidence interval estimate of the difference between type 1 and type 2 yields. What does the confidence interval suggest about farmer Joe's claim that type 1 seed is better than type 2 seed?
Type 1 |
2005 |
2089 |
2059 |
2496 |
2143 |
1956 |
2099 |
1453 |
|
---|---|---|---|---|---|---|---|---|---|
Type 2 |
2014 |
1971 |
2043 |
2461 |
2104 |
1946 |
2108 |
1409 |
In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the type 1 seed yield minus the type 2 seed yield. The 95% confidence interval is
= ____<μd< ____
(Round to two decimal places as needed.)
What does the confidence interval suggest about farmer Joe's claim that type 1 seed is better than type 2 seed?
A. Because the confidence interval only includes positive values and does not include zero, there is not sufficient evidence to support farmer Joe's claim.
B. Because the confidence interval only includes positive values and does not include zero, there is sufficient evidence to support farmer Joe's claim.
C. Because the confidence interval includes zero, there is sufficient evidence to support farmer Joe's claim.
D. Because the confidence interval includes zero, there is not sufficient evidence to support farmer Joe's claim.
Type 1 | Type 2 | difference |
2005 | 2014 | -9 |
2089 | 1971 | 118 |
2059 | 2043 | 16 |
2496 | 2461 | 35 |
2143 | 2104 | 39 |
1956 | 1946 | 10 |
2099 | 2108 | -9 |
1453 | 1409 | 44 |
Type 1 | Type 2 | difference |
2005 | 2014 | -9 |
2089 | 1971 | 118 |
2059 | 2043 | 16 |
2496 | 2461 | 35 |
2143 | 2104 | 39 |
1956 | 1946 | 10 |
2099 | 2108 | -9 |
1453 | 1409 | 44 |
xbar = 30.5
s = 40.85
n = 8
t-value for 95% CI is 2.365
CI = (xbar - t*s/sqrt(n) , xbar - t*s/sqrt(n))
CI = (30.5 - 2.365*40.85/sqrt(8) , 30.5 + 2.365*40.85/sqrt(8))
= (-3.66, 64.66)
D. Because the confidence interval includes zero, there is not
sufficient evidence to support farmer Joe's claim.
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