A standardized test was given to 6000 students. The scores were normally distributed with a mean of 380 and a standard deviation of 50. How many students scored between 280 and 380?
Solution =
Given, X follows Normal distribution with,
= 380
= 50
Find P( 280 < x< 380 )
= P(X < 380 ) - P(X < 280)
= P[(X - )/ < (380 - 380)/50] - P[(X - )/ < (280 - 380)/50]
= P[Z < 0.00] - P[Z < -2.00]
= 0.5 - 0.0228 ..Use z table
= 0.4772
Answer : P( 280 < x< 380 ) = 0.4772
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