The widths of 79 randomly selected window blinds were found to have a standard deviation of 2.37. Calculate the 95% confidence interval for the population standard deviation of the widths of all window blinds in this factory. Round your answers to 2 decimal places.
1Lower Bound ?
2Upper Bound?
Chi square critical values at 0.05 level with 78 df = 55.466 , 104.316
95% confidence interval for is
Sqrt [ (n-1) S2 / /2 ] < < Sqrt [ (n-1) S2 / 1-/2 ]
sqrt [ ( 79 - 1) * 2.372 / 104.316 ] < < sqrt [ ( 79 - 1) * 2.372 / 55.466 ]
2.05 < < 2.81
Lower bound = 2.05
Upper bound = 2.81
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