*Please do this question in Minitab*
The Response Rate Data
A study was designed to see if a mail survey’s response rate could be improved by contacting the potential respondents before they received the survey. One group of individuals received a preliminary letter about the survey, the second group was phoned, and the third group received no preliminary contact. The table below gives the counts of responses (yes/no) two weeks after the survey was mailed. (ref: Moore & McCabe, Intro Practice of Statistics, third edition, Freeman)
Intervention |
|||
Response? |
Letter |
Phone Call |
None |
Yes |
171 |
146 |
118 |
No |
220 |
68 |
455 |
Total |
391 |
214 |
573 |
Did the intervention make a difference? If so, what was the difference?
c1 | c2 | c3 | sum | |||||
r1 | 171 | 146 | 118 | 435 | ||||
r2 | 220 | 68 | 455 | 743 | ||||
sum | 391 | 214 | 573 | 1178 | ||||
Eij | 1 | 2 | 3 | |||||
expected | 1 | 144.3846 | 79.02377 | 211.5917 | ||||
2 | 246.6154 | 134.9762 | 361.4083 | |||||
0i | 171 | 146 | 118 | 220 | 68 | 455 | ||
Ei | 144.3846 | 79.02377 | 211.5917 | 246.6154 | 134.9762 | 361.4083192 | ||
sum | ||||||||
(Oi-Ei)^2/Ei | 4.906219 | 56.7654 | 41.39767 | 2.872416 | 33.23411 | 24.23685968 | 163.4127 | |
critical value | 5.991465 | |||||||
p-value | 3.28E-36 |
df = 2
TS = 163.41
critical value = 5.99 for alpha = 0.05
since TS > critical value
we reject the null hypothesis
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