For a particular policyholder, the number of losses during the next year, N, follows a
Poisson distribution with ?=2.5.
If a loss occurs, the amount of each loss, X, has the following distribution listed below.
The number of losses is independent of the amount of a loss.
x | p(x) |
120 | 0.40 |
160 | 0.45 |
300 | 0.15 |
Let S represent aggregate losses during the next year.
(a) Calculate E(S).
(b) Determine Var(S).
(c) Calculate P(S < 250).
Here
So,
Also,
and,
So,
a)
If , then,
b)
If , then,
c)
Required probability =
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