Scores on a recent national statistics exam were normally distributed with a mean of 82 and a standard deviation of 4.
Given that, mean = 82
stsndard deviation = 4
i) We want to find, P(X >= 87)
Therefore, required probability is 0.1056
ii) We want to find, P(80 < X < 85)
Therefore, required probability is 0.4649
iii) We want to find, the value of x such that, P(X > x) = 0.03
Therefore, lowest score eligible for an award is 89.52
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