Let X denote the amount of time for which a statistics reference book, on two-hour reserve at the library, is checked out by a randomly selected student. Suppose that X has the following probability density function (pdf) f(x)=kx2(2−x), 0≤x≤2.
(a) Find the cumulative distribution function (cdf) of X (Hint: Don’t forget that first you have to find k).
(b) Find the probability that the book is checked out for a time between 0.5 and 1.5 hours.
(c) Find the probability that the book is checked out for less than 1.5 hours, given that is checked out for more than 1 hour. 5
(d) Find the expected amount of time for which the book is checked out.
for this to be valid: f(x) dx must be 1
f(x) dx =k(2x2-x3) dx =k*(2x3/3-x4/4)|20 =k*(4/3)=1
k=3/4
a)
CDF =F(x)=P(X<x)= f(x) dx= (3/4)(2x2-x3) dx =(3/4)*(2x3/3-x4/4)|x0 =(3/4)*(2x3/3-x4/4)
b)
P(0.5<X<1.5)=F(1.5)-F(0.5)=(3/4)*(2*1.53/3-1.54/4)-(3/4)*(2*0.53/3-0.54/4)=0.6875
c)
P(X<1.5|X>1)=P(1<X<1.5)/P(X>1.5) =(F(1.5)-F(1))/(1-F(1.5))=(0.7383-0.3125)/(1-0.3125)=0.6193
d)
expeted time =E(X)=x f(x) dx =(3/4)(2x3-x4) dx =(3/4)*(2x4/4-x5/5)|20 =6/5 =1.2
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