Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is muμequals=17.00Mbps. The sample size is nequals=26 and the test statistic is tequals=2.336
Here, the sample size n = 26
Test statistic t = 2.336
d.f. = n - 1 = 26 - 1 = 25
Null hypothesis H0 : = 17.00 MbPs
Alternative hypothesis H1 : 17.00 MbPs
P value for t with d.f 25 is P(t > 2.336) = TDIST(2.336, 25, 2) = 0.0278
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