The amount of time a bank teller spends with each customer has a population mean, mu, of 2.80 minutes and a standard deviation, sigma, of 0.50 minute.
d. If you select a random sample of 100 customers, there is an 85% chance that the sample mean is less than how many minutes?
Given that,
mean = = 2.80
standard deviation = = 0.50
n = 100
= 2.80
= / n = 0.50 / 100 = 0.05
P(Z < 1.04) = 0.85
z = 1.04
= z * + = 1.04 * 0.05 + 2.80 = 2.852
Answer = 2.852
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