Question

A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess board. On the second square the King would place two grains of​ wheat, on the third​ square, four grains of​ wheat, and on the fourth square eight grains of wheat. If the amount of wheat is doubled in this way on each of the remaining​ squares, how many grains of wheat should be placed on square 23​? Also find the total number of grains of wheat on the board at this time and their total weight in pounds.​ (Assume that each grain of wheat weighs​ 1/7000 pound.)

Answer 1

The number of grains in i​​​​​​th square follows a pattern of

grains of wheat

Thus, number of grains of wheat to be placed on square 23 = = 4,194,304

Total number of grains of wheat on the board

= = =

Total weight of the grains of wheat on the board

= 1/7000*1.84467E19

= pounds