1.Joe is playing a game of chance at the hibiscus festival, costing $1 for each game. In the game two fair dice are rolled and the sum of the numbers that turned up is found. If the sum is seven, then Joe wins $5. Otherwise loses his money. Joe play the game 15 times. Find his expected profit or lose?
2. The basketball player has a 75% chance of a successful shot. The shots are assumed to be independent of each other. Find the probability that 3 out of the next 4 shots are successful?
3.
(1)
S = {(1, 1), (1, 2), (1, 3) ... (6, 4), (6, 5), (6, 6)} and n(S) = 36
A = Sum is 7 = {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)} and n(A) = 6
P(Win) = n(A)/n(S) = 6/36 = 1/6 = 0.1667
P(Lose) = 1 - 0.1667 = 0.8333
Profit (x) | P(x) |
$4 | 0.1667 |
$-1 | 0.8333 |
Expected profit per game = $4 * 0.1667 + $-1 * 0.8333 = $-0.1667
In 15 games, Joe is expected to lose 15 * $0.1667 = $2.50
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