I developed an achievement test and normalized it on people throughout the country over a year. My test has scores that are normally distributed with a mean of 100 and a standard deviation of 20. a. Find the probability that a randomly selected adult has IQ < 115 b. Find the probability that a randomly selected adult has IQ > 70 c. Find P30, which is the IQ score at the 30th percentile. d. What percentage of adults have scores between 80 and 120?
Here we have
(a)
The z-score for X = 115 is
The probability that a randomly selected adult has IQ < 115 is
Answer: 0.7734
(b)
The z-score for X = 70 is
The probability that a randomly selected adult has IQ > 70 is
Answer: 0.9332
(c)
Here we need z-score that has 0.30 area to its left. Using z table, z-score -0.52 has approximately 0.30 area to its left. So required X is
Answer: 89.6
(d)
The z-score for X = 80 is
The z-score for X = 120 is
The required percentage is
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