A medical researcher believes that a drug changes the body's temperature. Seven test subjects are randomly selected and the body temperature of each is measured. The subjects are then given the drug, and after 30 minutes, the body temperature of each is measured again. The results are listed in the table below. Is there enough evidence to conclude that the drug changes the body's temperature?
Let d=(body temperature after taking drug)−(body temperature before taking drug)d=(body temperature after taking drug)−(body temperature before taking drug). Use a significance level of α=0.01 for the test. Assume that the body temperatures are normally distributed for the population of people both before and after taking the drug.
Subject | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
---|---|---|---|---|---|---|---|
Temperature (before) | 99.1 | 99.9 | 98.9 | 98.8 | 99.7 | 99.8 | 99.9 |
Temperature (after) | 98.8 | 99.3 | 99.6 | 98.5 | 99.5 | 99.3 | 99.4 |
Step 1 of 5: State the null and alternative hypotheses for the test.
Step 2 of 5: Find the value of the standard deviation of the paired differences. Round your answer to one decimal place.
Step 3 of 5: Compute the value of the test statistic. Round your answer to three decimal places.
Step 4 of 5: Find the p-value for the hypothesis test. Round your answer to four decimal places.
Step 5 of 5: Draw a conclusion for the hypothesis test.
Step 1 of 5:
H0:Null Hypothesis:
HA: Alternative Hypothesis:
Step 2 of 5:
d = After - Before are got as follows:
- 0.3, - 0.6, 0.7, - 0.3, - 0.2, - 0.5, - 0.5
= - 1.7/7 = - 0.2429
Standard deviation of paired differences is given by:
sd = 0.4
Step 3 of 5:
SE = sd/
= 0.4392/ = 0.1660
Test statistic is given by:
t = - 0.2429/0.1660 = - 1.463
Step 4 of 5:
ndf = 7 - 1 = 6
By Technology, P - Value = 0.1938
Step 5 of 5:
Since P - value = 0.1938 is greater than = 0.01, the difference is not significant.Fail to reject null hypothesis.
Conclusion:
The data do not support the claim that the drug changes the body temperature.
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