Compute the linear correlation coefficient from the given table. X 1 2 4 6 7 Y 17 13 9 6 4
Solution :
X | Y | XY | X^2 | Y^2 |
1 | 17 | 17 | 1 | 289 |
2 | 13 | 26 | 4 | 169 |
4 | 9 | 36 | 16 | 81 |
6 | 6 | 36 | 36 | 36 |
7 | 4 | 28 | 49 | 16 |
n | 5 |
sum(XY) | 143.00 |
sum(X) | 20.00 |
sum(Y) | 49.00 |
sum(X^2) | 106.00 |
sum(Y^2) | 591.00 |
Numerator | -265.00 |
Denominator | 268.37 |
r | -0.9875 |
r square | 0.9751 |
Xbar(mean) | 4.0000 |
Ybar(mean) | 9.8000 |
SD(X) | 2.2804 |
SD(Y) | 4.7074 |
b | -2.0385 |
a | 17.9538 |
Linear correlation coefficient = -0.9875
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