Suppose that the random variable X follows a normal distribution with mean 35 and variance 25.
a.) Calculate P(X > 37)
b.) Calculate P(32 < X < 38)
c.) Find the value of x so that P(X >x) is approximately 0.975
Solution :
Given that ,
mean = = 35
variance = 25
standard deviation = = 5
(a)
P(x > 37) = 1 - P(x < 37)
= 1 - P[(x - ) / < (37 - 35) / 5]
= 1 - P(z < 0.4)
= 0.3446
(b)
P(320 < x < 38) = P[(32 - 35)/ 5) < (x - ) / < (38 - 35) /5 ) ]
= P(-0.6 < z < 0.6)
= P(z < 0.6) - P(z < -0.6)
= 0.415
(c)
P(Z < -1.96) = 0.025
z = -1.96
Using z-score formula,
x = z * +
x = -1.96 * 5 + 35 = 25.2
x = 25.2
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