Given a normal distribution with muequals103 and sigmaequals25, and given you select a sample of n equals 25, complete parts (a) through (d).
d. There is a 63% chance that Upper X overbar is above what value?
Given that,
mean = = 103
standard deviation = = 25
n = 25
= 103
= / n = 25 / 25 = 5
P(Z < -0.33) = 0.37
z = -0.33
= z * + = -0.33 * 5 + 103 = 101.35
Value = 101.35
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