5 fair 8-sided dice are rolled. |
(a) | Find the conditional probability that at least one die lands on 3 given that all 5 dice land on different numbers. |
Bayes' Theorem: P(A | B) = P(A & B)/P(B)
Number of ways in which 5 different numbers can be landed = 8C5
= 56
Number of ways in which 5 different numbers can b elanded such that 1 number is 3 = 1 x Number of ways in which 4 numbers can be landed from 7
= 1 x 7C4
= 35
P(at least one die lands on 3 given that all 5 dice land on different numbers) = Number of ways in which 5 different numbers can b elanded such that 1 number is 3 / Number of ways in which 5 different numbers can be landed Number of ways in which 5 different numbers can be landed
= 35/56
= 0.625
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