A fair 4-sided die is rolled 7 times. |
(a) | Find the probability that the side 1 comes up exactly 3 times. |
(b) | Find the probability that there is at least one side that comes up exactly 3 times. |
Binomial distribution: P(X) = nCx px qn-x
a) P(side 1), p = 1/4
q = 1 - 1/4 = 3/4
Number of rolls, n = 7
a) P(the side 1 comes up exactly 3 times) = 7C3 x (1/4)3 x (3/4)4
= 0.1038
b) P(at least one side that comes up exactly 3 times) = P(1 comes up exactly 3 times) + P(2 comes up exactly 3 times) + P(3 comes up exactly 3 times) + P(4 comes up exactly 3 times) - Number of ways to select 2 numbers from 4 x P(2 numbers comes up exactly 3 times)
= 0.1038x4 - 4C2 x (7C3 x 4C3) x (1/4)3 x (1/4)3 x (2/4)
= 0.4152 - 6x0.0171
= 0.3127
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