For parts a and b , use technology to estimate the following.
a) The critical value of t for a 90 % confidence interval with df=2.
b) The critical value of t for a 95 % confidence interval with df=104.
Solution :
Given that,
a ) Degrees of freedom = df = 2
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
t /2,df = t0.05,2 = 2.920
The critical value of t = 2.902
b ) Degrees of freedom = df = 104
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,104 = 1.983
The critical value of t = 1.983
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