Question

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. Margin of​ error: six percentage​ points; confidence level 95​%; from a prior​ study, ModifyingAbove p with caret is estimated by the decimal equivalent of 56​% nequals nothing ​(Round up to the nearest​ integer.)

Answer 1

Solution :

Given that,

= 56%=0.56

1 - = 1 - 0.56 = 0.44

margin of error = E = 6% = 0.06

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z_/2 = Z_0.025 = 1.96

Sample size = n = (Z_/2 / E)² * * (1 - )

= (1.96 / 0.06)² * 0.56 * 0.44

= 262.936 =263 (rounded)

Sample size = 263