Another type of painted ceramic vessel is called three-circle red-on-white ( Mimbres Mogollon Archaeology). At four different sites in an archaeological region, the number of such sherds was counted in local dwelling excavations.
Site I | Site II | Site III | Site IV |
19 | 15 | 38 | 13 |
22 | 8 | 15 | 17 |
5 | 30 | 10 | 16 |
22 | 8 | 47 | 37 |
10 | 24 | 19 | |
12 | 18 |
Shall we reject or not reject the claim that there is no difference in the population mean three-circle red-on-white sherd counts for the four sites? Use a 5% level of significance.
(a) What is the level of significance?
State the null and alternate hypotheses (from the following).
Ho: μ1 = μ2 = μ3 = μ4; H1: Not all the means are equal.
Ho: μ1 = μ2 = μ3 = μ4; H1: Exactly two means are equal.
Ho: μ1 = μ2 = μ3 = μ4; H1: Exactly three means are equal.
Ho: μ1 = μ2 = μ3 = μ4; H1: All four means are different.
(b) Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.)
SSTOT | = | |
SSBET | = | |
SSW | = |
Find d.f.BET, d.f.W,
MSBET, and MSW. (Use 3 decimal
places for MSBET, and
MSW.)
dfBET | = | |
dfW | = | |
MSBET | = | |
MSW | = |
Find the value of the sample F statistic. (Use 3 decimal
places.)
What are the degrees of freedom?
(numerator)
(denominator)
(c) Find the P-value of the sample test
statistic.
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis?
(e) Interpret your conclusion in the context of the
application.
(f) Make a summary table for your ANOVA test.
Source of Variation |
Sum of Squares |
Degrees of Freedom |
MS | F Ratio |
P Value | Test Decision |
Between groups | ---Select from the following--- p-value > 0.100 -- 0.050 < p-value < 0.100 -- 0.025 < p-value < 0.050 -- 0.010 < p-value < 0.025 -- 0.001 < p-value < 0.010 -- p-value < 0.001 | ---Select from following--- Do not reject H0. -- Reject H0. | ||||
Within groups | ||||||
Total |
Applying one way ANOVA: (use excel: data: data analysis: one way ANOVA: select Array): |
a)level of significance=0.05
Ho: μ1 = μ2 = μ3 = μ4; H1: Not all the means are equal.
b)
SSTOT | 2362.286 |
SSBET | 399.252 |
SSW | 1963.033 |
dfBET | 3 |
dfW | 17 |
MSBET | 133.084 |
MSW | 115.473 |
value of test statistic for factor A = | 1.153 |
df(numerator) = | 3 | |
df(Denominator) = | 17 |
c)
p value = 0.3566
d) fail to reject the null hypothesis
e) can not conclude that means are different
f)
Source | SS | df | MS | F | P value |
Between | 399.252 | 3 | 133.084 | 1.153 | 0.3566 |
Within | 1963.033 | 17 | 115.473 | ||
Total | 2362.286 | 20 |
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