Question

A survey of n = 50 people reveals that the proportion of residents in a community...

A survey of n = 50 people reveals that the proportion of residents in a community who take the bus to work is 0.15. Is this significantly different from the statewide average of 0.10? Use a significance level of 0.05. Write down the null and alternative hypotheses, find the test statistic and the p-value, and state your conclusion.

Homework Answers

Answer #1

To test against

Here

sample proportion

and sample size

The test statistic can be written as

which under H0 follows a standard normal distribution.

We reject H0 at 5% level of significance if P-value < 0.05

Now,

The value of test statistic =

and P-value =

Since P-value > 0.05, so we fail to reject H0 at 5% level of significance and we can conclude that the proportion of residents in a community who take the bus to work is not significantly different from the statewide average of 0.10.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
4. A researcher believes that the proportion of a community’s population in favor of a new...
4. A researcher believes that the proportion of a community’s population in favor of a new park is greater than the countywide proportion of 0.65. A survey of 67 people in the community reveals that the estimated proportion of the community in favor of it is equal to 0.76. Use alpha = 0.05. State the null and alternative hypotheses, find the test statistic, compare it with the critical value, make a decision, and find the p-value.
A researcher believes that the proportion of a community’s population in favor of a new park...
A researcher believes that the proportion of a community’s population in favor of a new park is greater than the countywide proportion of 0.65. A survey of 67 people in the community reveals that the estimated proportion of the community in favor of it is equal to 0.76. Use alpha = 0.05. State the null and alternative hypotheses, find the test statistic, compare it with the critical value, make a decision, and find the p-value.
4. A researcher believes that the proportion of a community’s population in favor of a new...
4. A researcher believes that the proportion of a community’s population in favor of a new park is greater than the countywide proportion of 0.65. A survey of 67 people in the community reveals that the estimated proportion of the community in favor of it is equal to 0.76. Use alpha = 0.05. State the null and alternative hypotheses, find the test statistic, compare it with the critical value, make a decision, and find the p-value. PLEASE HELP!
A study is made of residents in portland and its suburbs concerning the proportion of residents...
A study is made of residents in portland and its suburbs concerning the proportion of residents who subscribe to HBO. A random sample of 88 urban residents showed that 12 subscribed, and a random sample of 97 suburban residents showed that 18 subscribed. Does this indicate that a higher proportion of suburban residents subscribe to HBO? Use a 5% level of significance. a. State the null and alternative hypotheses ?0: ?1: b. What calculator test will you use? List the...
A government official claims that the proportion of residents of India who are undernourished is no...
A government official claims that the proportion of residents of India who are undernourished is no more than 0.10. An economist in the country, however, believes that the proportion of the Indian population who are undernourished is higher than 0.10. A random sample of 400 residents found that 70 were undernourished. Test the economist’s hypothesis at the 0.05 level of significance. Provide the p-value in your conclusion.
4. A survey of 35 individuals reveals that the proportion of people in a residential area...
4. A survey of 35 individuals reveals that the proportion of people in a residential area who patronize a particular supermarket is 0.42; a repeat of the survey in the following year, using 52 individuals finds that the proportion is 0.56. Find a 95% confidence interval for the difference in sample proportions. (3) PLEASE HELP!
Test the claim that the proportion of people who own cats is significantly different than 20%...
Test the claim that the proportion of people who own cats is significantly different than 20% at the 0.01 significance level. The alternative hypothesis would be: μ>0.2 p≠0.2 μ≠0.2 p>0.2 p<0.2 μ<0.2 The test is: right-tailed two-tailed left-tailed Based on a sample of 500 people, 16% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis The conclusion is: At the...
Hypothesis Test Example For Proportions: What proportion of people do not drink alcohol? You believe that...
Hypothesis Test Example For Proportions: What proportion of people do not drink alcohol? You believe that the proportion of people in the U.S.A. who do not drink is less than 15%. To determine if you are correct, you take a SRS of 400 U.S. residents, and find the proportion of people who do not drink in your sample is 0.22. Conduct a hypothesis test at the 5% significance level. A). Write the hypotheses for the test. B). Check the assumptions...
The proportion of people that own cats is 60%. A veterinarian believes that this proportion is...
The proportion of people that own cats is 60%. A veterinarian believes that this proportion is larger than 60% and surveys 400 people. Test the veterinarian's claim at the α=0.10 significance level. Preliminary: Is it safe to assume that n≤0.05 of all subjects in the population? Yes No Verify np(1−p)≥. Round your answer to one decimal place. np(1−p)= Test the claim: The null and alternative hypotheses are H0:μ≥0.6 Ha:μ<0.6 H0:μ=0.6 Ha:μ≠0.6 H0:p=0.6 Ha:p≠0.6 H0:p≤0.6 Ha:p>0.6 H0:μ≤0.6 Ha:μ>0.6 H0:p=0.6 Ha:p<0.6 The...
Self-reported injuries among left- and right-handed people were compared in a survey of 1896 college students...
Self-reported injuries among left- and right-handed people were compared in a survey of 1896 college students in British Columbia, Canada. Of the 180 left-handed students, 93 reported at least one injury. In the same period, 619 of the 1716 right-handed students reported at least one injury. Conduct a significance test to determine if the proportions of left-handed injured students is equal to the proportion of right-handed injured students. State clearly your conjecture, null and alternative hypotheses, test statistic, p-value, test...