Solution 3:
Given that mean, = 76, standard deviation, = 12 and sample size, = 36
The professor will deliver his promise when the class average is above 80 i.e. X > 80. We have to find P (> 80)
The respective Z- score with = 80 is
2
Now, we use Z-tables to find the probability of Z greater than 2
P (Z > 2) = 1 - P (Z 2)
= 1 - 0.9772
= 0.0228
Hence, the probability that he will have to deliver on his promise is 0.0228
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