Create a set of 5 positive numbers (repeats allowed) that have median 11 and mean 8. (Enter your answers as a comma-separated list.)
Since, median = 8 , n=5 ; this implies on arranging the observations in ascending order , the 3rd observation will be 11.
_ , _ , 11 , _ , _
Mean of 5 observations = 8
Thus , sum of 5 observations = 8*5 =40
sum of 4 unknown observations = 40-11 = 29
Now, we have to choose observation in a way first 2 observations should be less than or equal to median.
And the next 2 observations to be in the way that next 2 observations should be greater than or equal to median.
Some of the possible options are as follows:
(2,5,11,11,11)
(2,4,11,11,12)
(2,3,11,11,13)
(2,2,11,11,14)
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