Question

john has collected a sample of variable X in the following table: 32 52 36 26...

john has collected a sample of variable X in the following table:

32

52

36

26

43

23

25

26

14

38

27

19

14

35

Assume X follows a normal distribution with an unknown mean and standard deviation. Peter would like to calculate the 98% confidence interval, which allows him to do a two-tailed t-test to examine whether the mean of X is different from 30.

What is the critical t-value for this confidence interval?

What is the value of the standard error for this confidence interval?

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

calculate mean ans standard deviation for the sample data given,

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Dataset: Husband   Wife 53   50 38   34 46   44 30   36 31   23 26   31 29  ...
Dataset: Husband   Wife 53   50 38   34 46   44 30   36 31   23 26   31 29   25 48   51 65   46 29   26 28   23 29   32 25   22 22   21 21   24 43   50 24   27 38   33 33   26 35   29 40   29 27   25 27   24 49   38 48   39 27   27 26   24 40   34 35   37 21   26 32   39 30   28 60   52 36   40 25   23 66   55 52   34 41   40 43  ...
Consider the following times-series where the data is recorded weekly Data collected over 36 weeks t...
Consider the following times-series where the data is recorded weekly Data collected over 36 weeks t X t X t X t X t X t X 1 9.8 7 36.4 13 53.4 19 99.2 25 105.3 31 141.3 2 9.0 8 51.0 14 66.6 20 90.4 26 116.7 32 151.8 3 10.5 9 51.1 15 70.6 21 91.2 27 113.2 33 151.1 4 20.6 10 46.9 16 76.4 22 94.9 28 120.5 34 156.4 5 28.1 11 50.5 17...
A random variable ?x has a Normal distribution with an unknown mean and a standard deviation...
A random variable ?x has a Normal distribution with an unknown mean and a standard deviation of 12. Suppose that we take a random sample of size ?=36n=36 and find a sample mean of ?¯=98x¯=98 . What is a 95% confidence interval for the mean of ?x ? (96.355,99.645)(96.355,99.645) (97.347,98.653)(97.347,98.653) (94.08,101.92)(94.08,101.92) (74.48,121.52)
The results of a sample of 372 subscribers toWiredmagazine shows the time spent using the Internet...
The results of a sample of 372 subscribers toWiredmagazine shows the time spent using the Internet during the week. Previous surveys have revealed that the population standard deviation is 10.95 hours. The sample data can be found in the Excel test data file. What is the probability that another sample of 372 subscribers spends less than 19.00 hours per week using the Internet? Develop a 95% confidence interval for the population mean If the editors of Wiredwanted to have the...
____________________________________________ The results of a sample of 372 subscribers to Wired magazine shows the time spent...
____________________________________________ The results of a sample of 372 subscribers to Wired magazine shows the time spent using the Internet during the week. Previous surveys have revealed that the population standard deviation is 10.95 hours. The sample data can be found in the Excel test data file. What is the probability that another sample of 372 subscribers spends less than 19.00 hours per week using the Internet? ____________________________________________ Develop a 95% confidence interval for the population mean ____________________________________________ If the editors...
Treatment A Treatment B Treatment C 32 44 34 30 43 37 30 44 36 26...
Treatment A Treatment B Treatment C 32 44 34 30 43 37 30 44 36 26 46 37 32 48 41 Sample mean 30 45 37 Sample variance 6 4 6.5 a. At the X= 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error Calculate the value...
The following table gives the age (in years) of 36 randomly selected U.S. millionaires. The sample...
The following table gives the age (in years) of 36 randomly selected U.S. millionaires. The sample mean x−=58.53 years. Assume that the standard deviation of ages of all U.S. millionaires is 13.0 years. (See data on file: M07_Age_Millionaire_Q9.txt.) Obtain a 95% confidence interval for μ, the mean age of all U.S. millionaires. Interpret the confidence interval obtained in part (a). According to the confidence interval obtained in part (b), could you claim that average age of all U.S. millionaires is...
B. Determine whether or not the table is a valid probability distribution of a discrete random...
B. Determine whether or not the table is a valid probability distribution of a discrete random variable. Explain fully. X 0.23 0.14 0.17 P(X=x) -0.22 0.38 0.84 Daily sales of a medium sized restaurant are normally distributed with a mean of $720 and a standard deviation of $80. What is the probability that a randomly selected day will make a sales of at least $656? What is the probability that a randomly selected day will make a sales between $680...
Given two dependent random samples with the following results: Population 1 19 26 26 30 48...
Given two dependent random samples with the following results: Population 1 19 26 26 30 48 33 31 Population 2 24 38 40 38 39 41 29 Use this data to find the 98% confidence interval for the true difference between the population means. Let d=(Population 1 entry)−(Population 2 entry)d=(Population 1 entry)−(Population 2 entry). Assume that both populations are normally distributed. Step 1 of 4 :  Find the mean of the paired differences, x‾d. Round your answer to one decimal place....
Let the following sample of 8 observations be drawn from a normal population with unknown mean...
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation: 16, 26, 20, 14, 23, 10, 12, 29. [You may find it useful to reference the t table.] a. Calculate the sample mean and the sample standard deviation. (Round intermediate calculations to at least 4 decimal places. Round "Sample mean" to 3 decimal places and "Sample standard deviation" to 2 decimal places.) b. Construct the 95% confidence interval for the population...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT