A diet doctor claims that the average North American is more than 20 pounds overweight. To test his claim, a random sample of 30 North Americans was weighted, and the difference between their actual weight and their ideal weight was calculated. The sample mean is 20.85 pounds and the sample standard deviation is 3.76 pounds. Find the p-value for this hypothesis test. H_{a} \:: \mu >20 H a : μ > 20 pounds
Solution :
This is the right tailed test .
The null and alternative hypothesis is ,
H0 : = 20
Ha : > 20
Test statistic = t3.7
= ( - ) / s / n
= (20.85 - 20) / 3.76 / 30
= 1.24
df = 29
P-value = 0.1125
= 0.05
P-value >
Fail to reject the null hypothesis .
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