The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5,700. The income is normally distributed. If I take a sample of size 132, a) What is the distribution of the sample mean(shape)? b) Find the average of the sample means? c) Find the sample standard deviation?
Solution :
Given that ,
mean = = $28520
standard deviation = = $5700
n = 132
sample distribution of sample mean is ,
=
= 28520
sampling distribution of sample standard deviation
= / n = 5700 / 132=496.1213
= 496.1213
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