Question

The mean annual income for adult women in one city is $28,520 and the standard deviation...

The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5,700. The income is normally distributed. If I take a sample of size 132, a) What is the distribution of the sample mean(shape)? b) Find the average of the sample means? c) Find the sample standard deviation?

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Answer #1

Solution :

Given that ,

mean = = $28520

standard deviation = = $5700

n = 132

sample distribution of sample mean is ,

=

= 28520

sampling distribution of sample standard deviation

=  / n = 5700 / 132=496.1213

= 496.1213

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